Question #8cd79

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Question #8cd79

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Answer 1 · 2017-11-27T14:32:06

$1$ $1$

Explanation:

${cos}^{2} (180^{\circ}) = {cos 180}^{\circ} \times {cos 180}^{\circ}$ $cos^2(180^@)=cos180^@xxcos180^@$

$note that {cos 180}^{\circ} = - 1$ $"note that "cos180^@=-1$

$\Rightarrow {cos}^{2} (180^{\circ}) = {(- 1)}^{2} = 1$ $rArrcos^2(180^@)=(-1)^2=1$

Answer 2 · 2017-11-27T14:32:14

The value of ${cos}^{2} (180)$ $cos^2(180)$ is 1.

Explanation:

${cos}^{2} (180) = cos (180) \cdot cos (180)$ $cos^2(180) = cos(180) * cos(180)$

By the unit circle, $cos (180) = - 1$ $cos(180) = -1$

Substituting for $cos (180)$ $cos(180)$ gives

${cos}^{2} (180) = - 1 \cdot - 1 = 1$ $cos^2(180) = -1 * -1 = 1$

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Question #8cd79

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