How do you simplify #\frac { 3} { 21x ^ { 2} } \cdot 24x ^ { 3}#?

2 Answers
Nov 28, 2017

#(24x)/7#

Explanation:

Given: #3/(21x^2)*24x^3#

We begin by cancelling the like terms, that is;
#cancel(3)/(cancel(21)cancel(x^2))*24cancel(x^3) = (color(red)(24)color(red)(x))/color(red)7#

Nov 28, 2017

#(24x)/7#

Explanation:

#3/(21x^2)xx(24x^3)/1#

#color(blue)"cancel common factors ""on numerator/denominator"#

#cancel(3)^1/(cancel(21)^7xx cancel(x)xxcancel(x))xx(24xx cancel(x)xxcancel(x)xx x)/1#

#=(24x)/7#