How do you graph $f (x) = {(x - 4)}^{2} + 5$ $f(x) = (x-4)^2+5$ ?

Question

1922 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-29T05:48:36

here is the graph:
enter image source here

Compare $f (x) = {(x - p)}^{2} + q$ $f(x)=(x-p)^2+q$ to $f (x) = {(x - 4)}^{2} + 5$ $f(x)=(x-4)^2+5$

$v e r t e x = (p, q)$ $vertex= (p,q)$

so, the vertex of the graph is (4,5).
find the point on the graph.

Then draw accordingly.

How do you graph f(x)=(x−4)2+5f(x) = (x-4)^2+5?