Question #bdba5

1 Answer
Nov 30, 2017

#ln (5x^5(x^2+5)^2)#

Explanation:

There are two properties of logarithms that will help us out here:
1) #ln a^b=b*lna#
2) #ln a*b=lna+lnb#

So, first we use property #1 to take the constants out from the front of the logs, making our equation look like this:

#ln5+ln x^5+ln(x^2+5)^2#

Now, we use property #2 to join all the terms under one log, resulting in this:

#ln (5x^5(x^2+5)^2)#