How do you evaluate the expression #(23!)/(2!10!)#?

1 Answer
José F.
Dec 2, 2017

Just use the properties of factorials: 23⋅22⋅21⋅20⋅19⋅18⋅17⋅16⋅15⋅14⋅13⋅6⋅11

Explanation:

#(23!)/(2!\10!)=#

#(23*22*21*20*19*18*17*16*15*14*13*12*11*10!)/(2*10!)=#

#(23...14*13*(cancel(2)*6)*11*cancel(10!))/(cancel(2*10!)#

#=23*22*21*20*19*18*17*16*15*14*13*6*11#

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