How do you evaluate $7^{2} - 4^{2} \times 3$ $7^ { 2} - 4^ { 2} \times 3$ ?

Question

1526 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-03T02:25:29

1

Follow BEDMAS (Bracket, exponent, division, multiplication, addition, subtraction)

Let's solve the exponents first, so:

$7^{2} - 4^{2} \cdot 3$ $7^2-4^2*3$

$= 49 - 16 \cdot 3$ $= 49 - 16 *3$

Following BEDMAS, we multiply next

$49 - 16 \cdot 3$ $49-16*3$

$= 49 - 48$ $=49-48$

And then we subtract

$49 - 48 = 1$ $49-48=1$

How do you evaluate 72−42×37^ { 2} - 4^ { 2} \times 3?