What is #(4x^4-6x^3+6x-7)/(-2x^2+3)#?

1 Answer
Morgan S.
Dec 3, 2017

#-2x^2+3x-3+\frac{-3x+2}{-2x^2+3}#

Explanation:

See the picture for the division process. The #0#’s as coefficients for #x#’s are there because each degree below the highest degree must be represented in the long division process.

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