Question #78e48
1 Answer
Dec 3, 2017
Due to steric hindrance, When the base is bulky, it will preferentially remove the most accessible hydrogen to avoid steric repulsion.
Explanation:
Hofmann's Elimination reactions takes place:
- When the base is larger
- When alkyl halide contains one or more double bond at
#gamma#
carbon - When the leaving group is poor such as F,NR3+,SR2+.
A bulky base removes the most accessible hydrogen and will be from the end of the substrate and hence least substitutedproduct.
{when alkyl halide contain one or more double bond then less substituted alkene may be major becase conjugated double bonds are more stable than isolated double bond.}