Question

Question #35fdb

Answer 1

See a solution process below:

Explanation:

If the problem is to solve: `4/7x = 1/3`

Then multiply each side of the equation by `color(red)(7)/color(blue)(4)` to solve for `x` while keeping the equation balanced:

`color(red)(7)/color(blue)(4) xx 4/7x = color(red)(7)/color(blue)(4) xx 1/3`

`cancel(color(red)(7))/cancel(color(blue)(4)) xx color(blue)(cancel(color(black)(4)))/color(red)(cancel(color(black)(7)))x = (color(red)(7) xx 1)/(color(blue)(4) xx 3)`

`x = 7/12`

If the problem is to solve: `4/(7x) = 1/3`

Then multiply each side of the equation by `color(red)(3)color(blue)(x)` to solve for `x` while keeping the equation balanced:

`color(red)(3)color(blue)(x) xx 4/(7x) = color(red)(3)color(blue)(x) xx 1/3`

`color(red)(3)cancel(color(blue)(x)) xx 4/(7color(blue)(cancel(color(black)(x)))) = cancel(color(red)(3))color(blue)(x) xx 1/color(red)(cancel(color(black)(3)))`

`(color(red)(3) xx 4)/7 = color(blue)(x) xx 1`

`12/7 = x`

`x = 12/7`

Answer 2

You can solve it with cross multiplication!

Explanation:

We begin with your given equation: `4/7x=1/3`

On the left side of your equation, you can multiply `x` by `4/7` to get `(4x)/7`.

Next, we cross multiply both sides of your equation.

`(4x)/7=1/3`
`(4x)(3)=(7)(1)`

It's simple algebra from there!

`12x=7`
`x=7/12`