Question

Question #e7dd8

Answer 1

4.76 mL

Explanation:

The molar mass of `H_2SO_3=82.01gmol^(-1)`

Molar number of`H_2SO_3=(0.0351 g)/(82.01gmol^(-1))=4.28xx10^(-4)mol`

Molarity of `H_2SO_3=S1=4.28xx10^(-4)molxx1000ml1/(250ml)=1.712xx10^(-3)M`

Reaction:

`H_2SO_3+2NaOH->Na_2SO_3+2H_2O`
1mole of `H_2SO_3` reacts with 2 mole NaOH.
`Suppose`,

S1=Molarity of `H_2SO_3=1.712xx10^(-3)M`,V1=Volume of

`H_2SO_3=250 mL`

S2=Molarity of NaOH=.18M,V2=Volume of NaOH=?

`((S1V1)(H_2SO_3))/((S2V2)(NaOH))=1/2`

=)V2=`(2S1V1)/(S2)=4.76 mL`