What is the molarity of an HCl solution if 25.0 mL of a 0.13 M NaOH solution are needed to neutralize 30.0 mL of the sample?

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Answer 1 · 2017-12-04T03:49:34

0.11 M

Balanced reaction:

$HCl + NaOH ⇌ H_2O + NaCl$

By titration:

$0.025$ $L$ of $0.13$ $(mol)/L$ $NaOH = 0.00325$ $mol$ $NaOH$

$0.00325$ $mol$ $NaOH$ $*$ $1$ $mol$ $HCl$ $/1$ $mol$ $NaOH$ =

$0.00325$ $mol$ $HCl$

Now,

$0.00325$ $mol$ $HCl$ $/$ $0.030$ L = $0.0108M$ $HCl$