Question

What is the molarity of an HCl solution if 25.0 mL of a 0.13 M NaOH solution are needed to neutralize 30.0 mL of the sample?

Answer 1

0.11 M

Explanation:

Balanced reaction:

`HCl + NaOH ⇌ H_2O + NaCl`

By titration:

`0.025` `L` of `0.13` `(mol)/L` `NaOH = 0.00325` `mol` `NaOH`

`0.00325` `mol` `NaOH` `*` `1` `mol` `HCl` `/1` `mol` `NaOH` =

`0.00325` `mol` `HCl`

Now,

`0.00325` `mol` `HCl` `/` `0.030` L =`0.0108M` `HCl`