$50g$ of pure $CaCO_3$ is heated, liberated $CO_2$ reacted 0.4 mol of moist ammonia to yield only $(NH_4_2CO_3$ . Find the volume of 3 $CO_2$ left after the reaction at STP?

Question

A) zero
B) $6.72L$
C) $2.24L$
D)indeterminate from this data

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Answer 1 · 2017-12-04T12:50:19

6.72L

Chemical reaction: **2 $NH_3 + + CO_2 rArr NH_2COONH_4$ **

NH3 reacts with CO2 to give Ammonium carbamate.

Moles of $CO_2$ taken:50/100=0.5 mol

Moles of $NH_3$ reacted $rarr$ 0.4 mol{given}

According to the reaction:
2 moles of $NH_3$ react with $rarr$ 1 mole of $CO_2$

For the reaction of 0.4 mole of $NH_3 rarr$ 1/2 $xx$ 0.4 mol of CO2 reacted, $rarr$ 0.4 $xx$ 0.5 moles of $CO_2$

moles of $CO_2$ left after reaction= moles taken $-$ moles reacted
$=$ 0.5 $-$ 0.4 $xx$ 0.5 $=$ 0.5(1 $-$ 0.4) $rArr$ 0.6/2 $rArr$ 0.3

moles of $CO_2$ left after reaction $rarr$ 0.3 moles

Volume of 0.3 moles of $CO_2=$ 22.4L $xx$ 0.3{1 mole $rArr$ 22.4L}
$rArr$ 6.72L