How much work would it take to push a # 1 kg # weight up a # 2 m # plane that is at an incline of # pi / 6 #?

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Answer 1 · 2017-12-04T14:29:04

9.8#sqrt#3

work done#=#F.s{F#rarr#Force acting;s#rarr#displacement}

W#=#Fscos#theta# where #theta# is the angle between force and the resulting displacement.

In this case the displacement is along the direction of force,{#theta##=#0}

W#=#Fs

here F#=#mgsin#theta#{gsin#theta# is the acceleration of the block kept on an inclined plane.}

Given s#=#2m
mass = 1Kg

substituting and solving:

W= Mg sin#theta##xx#s
#rArr#1Kg#xx#9.8m/s2#xx#2m#xx#sin#pi#/6#rArr#9.8#xx#2#xx##sqrt#3/2#=# #9.8##sqrt#3

You can also solve by finding the height of the plane{sin#pi#/6#=#H/s} and using W#=#mgh.{as work is a conservative force}