Question

Question #5239f

Answer 1

60mL

Explanation:

For the neutralisation of `V_1` mL of an acid { here HCL} with molarity `M_1` and basicity `n_a` by `V_2` mLof a base{ here Mg(OH)2} with molarity `M_2` and acidity `n_b`:

basicity of HCL`rArr`1

acidity of Mg(OH)2`rArr`2

`n_aM_1V_1` `=` `n_bM_2V_2`

1`xx`0.4M`xx`V1`=`2`xx`0.6M`xx`15mL

V1`=`1.2/0.4`xx`15mL `rArr`60mL