Question #5239f

1 Answer
Milan S#
Dec 4, 2017

60mL

Explanation:

For the neutralisation of #V_1# mL of an acid { here HCL} with molarity # M_1# and basicity # n_a# by #V_2# mLof a base{ here Mg(OH)2} with molarity #M_2# and acidity #n_b#:

basicity of HCL#rArr#1

acidity of Mg(OH)2#rArr#2

#n_aM_1V_1##= ##n_bM_2V_2#

1#xx#0.4M#xx#V1#=#2#xx#0.6M#xx#15mL

V1#=#1.2/0.4#xx#15mL #rArr#60mL

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