Question #bee0c

1 Answer
Dec 5, 2017

Volume#rArr#627mL

Explanation:

Volume of #H_2O_2# solution: 24.75mL.

Mass of #H_2O_2# solution#rArr##rho##xx#V#=# 24.75gm .

So lets find the moles of #H_2O_2# present in 24.75 gm solution

Given the solution contained 3.85% #H_2O_2# by mass#rArr#

100gm of the solution contain 3.85 gm of #H_2O_2# by mass

24.75gm solution contains#rarr# 3.85#xx(24.75)/(100)#

#color(red)rArr#0.9528 grams of #H_2O_2#

No. of Moles#=(0.9528)/(34)##rArr#0.0280

Molar volume of a gas at STP is 22.4 L/mol.

So volume occupied by 0.0280 moles of #H_2O_2#
#=#0.0280 mol #xx#22.4#(L)/(mol)##rArr##color(blue)0.6272 L#

Appro#rArrcolor(red)627mL#