Question #0624a
1 Answer
Heat required
Explanation:
The process can be split into 3 steps for simplification:
200 gms of ICE at
200 gms of WATER at
1 . In first step
200 gms of ICE at
The heat energy required is
[ Quantity of heat required to change 1 Kg of a substance from solid state to liguid state at its Melting point}
Latent heat of fusion of ICE
So heat required for 200gm
2.) 200 gms of WATER at
Q
SPECIFIC HEAT OF WATER
Q
3.) 200 gms of WATER at
Heat energy required is
{ Quantity of heat energy required to change its 1 kg mass from
liquid to vapour state at its boiling point,}
Latent heat of vaporisation of water:
536Kcal/gm
So heat required for vaporisation of 200gm water to steam at
The amount of heat (in Joules) required to convert 200 grams of ice
to gas at 100 degrees celsius is the sum heat of 3 steps