Question #62f84

1 Answer
Dec 6, 2017

weight of 7.25mol of #C_12H_24O_6=rArr1914g#

7.25 mol of #C_12H_24O_6# contains #7.25N_a# number of molecules.

Explanation:

Molecular weight of #C_12H_24O_6rArr264(g)/(mol)#.

weight of 7.25mol of #C_12H_24O_6=264(g)/(cancel(mol))xx7.25cancel(mol)#
#rArr1914g#

1 mole of a substance contains Avogadro number{#N_a#}of molecules.

7.25 mol of #C_12H_24O_6# contains #7.25N_a# number of molecules.