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In the reaction between $N O_{2}^{-}$ $NO_2^(-)$ and water, which species is the acid?

2 Answers

Dec 8, 2017

The $Bronsted acid$ $"Bronsted acid"$ is the proton donor....

Explanation:

And as written....

$N O_{2}^{-} + H_{2} O (l) ⇌ H N O_{2} (a q) + H O^{-}$ $NO_2^(-) + H_2O(l) rightleftharpoons HNO_2(aq) + HO^-$

....the $water molecule$ $"water molecule"$ is the $Bronsted acid$ $"Bronsted acid"$ , $the proton donor....$ $"the proton donor...."$

Do you agree?

Which is the $Bronsted base$ $"Bronsted base"$ ?

ChemCrazy · anor277

Dec 8, 2017

In the reaction between $N O_{2}^{-}$ $NO_2^(-)$ and water, which species is the acid?

Explanation:

The Bronted acid always donates a proton.

$underbrace(NO_2^(-))_"conjugate base" +H_2O -> underbrace(HNO_2)_"parent acid" + OH^-$

In this case, water donates a hydrogen to $NO_2$ to make $HNO_2$ . Water then becomes $OH^-$ since it lost one hydrogen.

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