Question

Question #ab934

Answer 1

Factor form: `(a - 12) (a - 13)`
Zeros: `x = 12, 13`

Explanation:

Assuming you want to factor `a^2 - 25a + 156` we first need to find the multiplies of `a^2` and `156`

`a^2 rarr a * a`
`156 hArr 1*156 hArr 2 * 78 hArr 3 * 52 hArr 4 * 39 hArr 6 * 26 hArr 12 * 13`

Let's go a head and try 12 * 13 as our factors

`a^2 - 25a + 156`
`(a - 12) (a - 13)`

By FOIL -ing we can check to see if our factors are correct

`(a - 12) (a - 13) rarr a^2 - 13a - 12a + 156 rarr a^2 - 25a + 156`

Setting the expression equal to zero we can solve for x giving us the zeros of the equation

`a^2 - 25a + 156 = 0`
`(a - 12) (a - 13) = 0` apply the zero product principle
`(a-12) = 0` and `(a - 13) = 0`

So our zeros are at `x = 12, 13`