Question #778cd

2 Answers
Dillin N.
Dec 10, 2017

#2sqrt(6)#

Explanation:

Begin by finding the prime factorization of 24 yielding

#24 rarr 2*12 rarr 2*2*6 rarr 2*2*2*3#

Rewriting the problem we've

#sqrt(2*2*2*3) rarr sqrt(2^2*2*3)#

When dealing with a Square Root we need to find prime factors that have a power of 2 (or groups of the same). In this case we have one such pair so we can move it to the outside and leave the rest inside alone yielding

#sqrt(2^2*2*3) rarr 2sqrt(2*3) rarr 2sqrt(6)#

Harold Walden
Dec 10, 2017

#sqrt24=2sqrt6#

Explanation:

#sqrt24=sqrt(4xx6)#
#sqrt(4*6)=sqrt4xxsqrt6#
#sqrt24=2sqrt6#

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