Question

Question #778cd

Answer 1

`2sqrt(6)`

Explanation:

Begin by finding the prime factorization of 24 yielding

`24 rarr 2*12 rarr 2*2*6 rarr 2*2*2*3`

Rewriting the problem we've

`sqrt(2*2*2*3) rarr sqrt(2^2*2*3)`

When dealing with a Square Root we need to find prime factors that have a power of 2 (or groups of the same). In this case we have one such pair so we can move it to the outside and leave the rest inside alone yielding

`sqrt(2^2*2*3) rarr 2sqrt(2*3) rarr 2sqrt(6)`

Answer 2

`sqrt24=2sqrt6`

Explanation:

`sqrt24=sqrt(4xx6)`
`sqrt(4*6)=sqrt4xxsqrt6`
`sqrt24=2sqrt6`