Evaluate the integral. ?

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1 Answer
Yiu A.
Dec 10, 2017

#-73/6#

Explanation:

#int_0^1 (u+3)(u-4)du#
#=int_0^1 (u^2-4u+3u-12)du#
#=int_0^1 (u^2-u-12)du#

Use #int x^n dx=x^(n+1)/(n+1)+C#

#=[u^3/3-u^2/2-12u]_0^1#

Using part 2 of fundamental theorem calculus:
#int_a^b f'(x) dx=f(b)-f(a)#

#=(1^3/3-1^2/2-12*1)-(0^3/3-0^2/2-12*0)#
#=1/3-1/2-12#
#=-73/6#

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