Question #ae58d

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Question #ae58d

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Answer 1 · 2017-12-12T02:27:29

There is only one possible isosceles triangle that can be drawn with one $80^{o}$ $80^o$

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Explanation:

An Isosceles Triangle by definition has two equal sides and two equal base angles.

Since the Sum of the angles of any triangle must be $180^{o}$ $180^o$ , we can solve for the value of the angles.

One angle must be $80^{o}$ $80^o$ based upon your question.

$x + x + 80^{o} = 180^{o}$ $x + x + 80^o = 180^o$

$2 x + 80^{o} = 180^{o}$ $2x + 80^o = 180^o$

$2 x + 80^{o} - 80^{o} = 180^{o} - 80^{o}$ $2x + 80^o - 80^o= 180^o - 80^o$

$2 x = 100^{o}$ $2x = 100^o$

$\frac{2 x}{2} = \frac{100^{o}}{2}$ $(2x)/2 = (100^o)/2$

$x = 50^{o}$ $x = 50^o$

Therefore the only triangle that can be drawn with only one $80^{o}$ $80^o$ angle also has two base angles of $50^{o}$ $50^o$ each. enter image source here

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