Question #7ad37

Question

925 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-13T14:48:30

The discriminant is #-28#, meaning there are no real solutions to the above function.

Given an equation in the form #ax^2+bx+c# where #a\neq 0#, the discriminant is given by #b^2-4ac#.

If . . .

#b^2-4ac > 0,# there are #2# real solutions.

#b^2-4ac =0,# there is #1# real solution.

#b^2-4ac < 0#, there are no real solutions.

In this case, the discriminant is #10^2-4(-4)(-8)#,

#\implies 100-128\implies -28#

#\therefore# there are no real solutions.