How many moles of silicon are in 1.67x10(24) Si atoms?

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How many moles of silicon are in 1.67x10(24) Si atoms?

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Answer 1 · 2017-12-14T13:44:34

$2.77 m o l$ $2.77 mol$

Explanation:

Ok, there is one important thing to remember here, Avogadro's number ( $6.022 \times 10^{23}$ $6.022×10^23$ ). So there is a great formula to solve this, here it is:

$x$ $x$ mol $\cdot \frac{6.022 \times 10^{23}}{1 m o l} = y$ $⋅(6.022×10^23)/(1 mol)=y$ atoms

So since we already know the atoms, lets plug that in and solve!

$y$ $y$ atoms $\cdot (\frac{1 m o l}{6.022 \times 10^{23}}) = x$ $*((1 mol)/(6.022×10^23))=x$ mol

$(1.67 \cdot 10^{24}) \cdot (\frac{1 m o l}{6.022 \times 10^{23}}) = x$ $(1.67*10^24)*((1 mol)/(6.022×10^23))=x$ mol

$2.77 = x$ $2.77=x$ mol

$2.77 m o l$ $2.77 mol$

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How many moles of silicon are in 1.67x10(24) Si atoms?

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