Question #2465d

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Question #2465d

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Answer 1 · 2017-12-14T15:11:07

The volume would be $274$ $274$ L.

Explanation:

[Step1] Find the amount of substance.

A mole of ideal gas has $6.02 \times 10^{23}$ $6.02xx10^23$ molecules.(This is the Avogadro's number.)
Since $N e$ $Ne$ is a monoatomic molecule, $7.28 \times 10^{24}$ $7.28xx10^24$ atmos are equivalent to $7.28 \times 10^{24}$ $7.28xx10^24$ molecules, and that is $\frac{7.28 \times 10^{24}}{6.02 \times 10^{23}} = 12.09$ $(7.28xx10^24)/(6.02xx10^23)=12.09$ moles.

[Step2] Find the volume.
A mole of ideal gas in STP( $0$ $0$ ℃, $1.0 \times 10^{5}$ $1.0xx10^5$ Pa) occupies $22.7$ $22.7$ L.
So, the volume of $12.09$ $12.09$ moles of Ne in STP is $12.09xx22.7=274.443≒274$ L.

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Question #2465d

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