Question #325c0

Question

1498 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-14T17:21:43

the fourth number in this sequence is $23$

Let's start by writing down what we know in an equation:

$x + (x+1)+(x+2)+(x+3)+(x+4)=110$

$5x+10=110$

$5x=100$

$x = 20$

of course, $x$ is the first integer in the sequence, so the fourth number is:

$x+3 = 23$

Answer 2 · 2017-12-14T17:23:38

See explanation.

The 5 consecutive integers can be expressed as:

$x$ , $x+1$ , $x+2$ , $x+3$ and $x+4$ . If we write their sum as an expression we get:

$5x+10$

If we solve the equation we get:

$5x+10=110=>5x=100=>x=20$

Now the fourth term in the sequence is: $x+3=23$

Answer 3 · 2017-12-18T18:32:42

I prefer to name my variables starting in the middle.

$n$ is the middle number.

The two less than $n$ are $n-1$ and $n-2$

The two numbers greater than $n$ are $n+1$ and $n+2$ .

The sum is $(n-2)+(n-1)+n+(n+1)+(n+2) = 5n = 110$

So $n = 110/5 = 22$

The fourth number is $n+1 = 22+1=23$