Question #390a5

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Answer 1 · 2017-12-15T03:31:42

$z$ $color(red)(z$ = 36.938 u

The average atomic mass of an element is the sum of each of its isotopes multiplied by its abundance percentage:

$avg. atomic mass = \sum i ({isotope}_{i} \times {abundance}_{i})$ $color(green )("avg. atomic mass" = sum_i ("isotope"_i xx "abundance"_i))$

Make
$z$ $color(red )(z$ : the atomic mass of chlorine-37

Substituting values in equation above

35.446 u = (34.969 u × 0.7577) + ( $z$ $color(red )(z$ × 0.2423)

Solving for z:

$z$ $color(red)(z$ = 36.938 u