Question

Question #708bc

Answer 1

6.95g

Explanation:

The equation for the decomposition of Iron (III) oxide (`Fe_2O_3`) is;

`2Fe_2O_3->3O_2+4Fe`

We need to know how many mols of `Fe_2O_3` we have in 23.11g

`"number of mols" = "mass(g)"/"Relative Molecular Mass(g per mol)"` = `"23.11"/"159.69"` = 0.14mols

From the reaction equation, we know that 2 mols of `Fe_2O_3` decomposes to produce 3 mols of `O_2`.

Therefore 0.14mols of `Fe_2O_3` will produce 0.21mols of `O_2`

Rearrange the previously used equation.

`"mass (g)" = "number of mols"*"Relative Molecular Mass(g per mol)"` = `0.21*32` = 6.95g