How do you solve 3u ^ { 2} - 5d \div 5= 0?

1 Answer
Dec 18, 2017

For d:
d=3u^2

For u:
u=+-sqrt(d/3)

Explanation:

3u ^ { 2} - 5d \div 5= 0

3u^2-(5d)/5=0

color(red)("Simplifying:")

3u^2-d=0

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color(green)("SOLVING FOR 'd':")

color(red)("Rearrange equation to isolate d:")

therefore d=3u^2

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color(green)("SOLVING FOR 'u':")

3u^2=d

color(red)("Divide both sides by 3:")

u^2=d/3

color(red)("Take square root of both sides:")

therefore u=+-sqrt(d/3)