How do you add #3\sqrt { 50} + \sqrt { 242}#?

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Answer 1 · 2017-12-19T17:34:45

#26sqrt(2)#

#3sqrt50+sqrt(242)#

The best first step is to decompose the radicand into prime factors:
#3sqrt(5^2*2)+sqrt(2*11^2)#

THen you pass all the squared prime numbers outside

#3*5sqrt(2)+11sqrt(2)#

Use #sqrt(2)# as an incognite:

#15sqrt(2)+11sqrt(2)#

#26sqrt(2)#