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Answer 1 · 2017-12-22T01:30:01

$=(56.0g)/(mol)$

Write and balance the equation.
$Fe+2HCl->FeCl_2+H_2$
Given the mass and concentration of $HCl$ , we can find the $etaHCl$ through this formula.
$"Molarity"=eta/"Li solution"$
$eta="Molarity"xx"Li solution"$
$eta=((2.2mol)/cancel((L)))((50.0cancel(mL))xx(1cancel(L))/(1000cancel(mL)))$
$eta=0.1100molHCl$
Now, find $etaFe$ through molar conversion with reference to the balanced equation for molar ratio.
$=0.1100cancel(molHCl)xx(1molFe)/(2cancel(molHCl))$
$=0.055molFe$
Lastly, find the relative atomic mass of $Fe$
$M_(Fe)=(mFe)/(etaFe)$
$M_(Fe)=(3.08g)/(0.055mol)$
$M_(Fe)=(56.0g)/(mol)$