Question #e2433

1 Answer
Dec 23, 2017

#1/2# times the original volume.

Explanation:

Just Recall The Combined Gas Law.

For an ideal gas,

#(P_iV_i)/T_i = (P_fV_f)/T_f#

If any work is done by or on the gas. (Well, It includes a lot of Thermodynamics.)

As per your question,

#P_f = 4P_i# (Remember the increase is three times, not the final pressure itself.)

And #T_f = 6T_i#

Putting the desired values in Places, we get,

#(P_iV_i)/T_i = (4P_i * V_f)/(6T_i)#

#rArr V_i = (4V_f)/6# (#P_i# and #T_i# get cancelled.)

#rArr V_f = (3V_i)/2#

So, Change in Volume = #DeltaV# = #V_f - V_i# = #1/2 V_i#

Hence Explained.