Question #b2872

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Answer 1 · 2017-12-25T14:23:57

$351.15 K$ $351.15 K$

We say that kelvin is equal to celsius + $273.15$ $273.15$ .

$C = K + 273.15$ $C=K+273.15$

Therefore,

$78 C = (78 + 273.15) K = 351.15 K$ $78C = (78 + 273.15)K = 351.15K$

Answer 2 · 2017-12-25T23:35:56

$= 351 K$ $=351K$

For easier conversion, better to memorize these important data than the confusing temperature scales' conversion formula.
$Boiling/Freezing Point of water in C = 100^{o} / 0^{o}$ $"Boiling/Freezing Point of water in " C=100^o"/"0^o$
$Boiling/Freezing Point of water in K = 373 / 273$ $"Boiling/Freezing Point of water in " K=373"/"273$
Set up the ratio and proportion to derive the conversion formula that can be formulated from the above data. Since these two scales have same size units; thus, 100 will be cancelled out.
$\frac{C - 0}{100 - 0} = \frac{K - 273}{373 - 273}$ $(C-0)/(100-0)=(K-273)/(373-273)$
$(C)/cancel((100))=(K-273)/cancel((100))$
$color(red)(C=K-273 " from " K to C$ $or"$
$color(blue)(K=C+273 " from " C to K$
Since these two temperature scales have different zero points and that $0^oC$ corresponds to $273K$ ; thus, conversion requires the addition of 273 to the $C$ as derived.
Given the value in $C$ , now find the temperature to be expressed in $K$ . Knowing the previously derived formula, plug in the value of $color(red)(C=78^o)$ ; thus,
$K=color(red)(C)+273$
$K=78+273$
$K=351$
Therefore $78^oC=351K$