How do you calculate the amount of heat needed to increase the temperature of 250g of water from 20 C to 56 C? $C_{g} = 4.8 \frac{J}{C - g}$ $C_g = 4.8 J/(C-g)$

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Answer 1 · 2017-12-26T07:13:31

$= 43.2 k J$ $=43.2kJ$

Given the data, the formula to use is
$Q=mCpDeltaT$
where:
$m=250g$
$DeltaT=T_2-T_1=56-20=36^oC$
$Cp=(4.8J)/(g*C)$
This case, just plug in given data to find the heat needed to raise the temperature of the water as provided in the problem.
$Q=(250cancel(g))((4.8J)/cancel((g*C)))(36^cancel(oC))$
$Q=43200J$
$Q=43.2kJ$

How do you calculate the amount of heat needed to increase the temperature of 250g of water from 20 C to 56 C? C_g = 4.8 J/(C-g)Cg=4.8JC−gC_g = 4.8 J/(C-g)