Find the angle between two vectors, 10 and 15 units long, when their resultant is (a) 20 units long and (b) 12 units long. Draw the appropriate figure?

1 Answer
Dec 30, 2017

"please see the solution below."

Explanation:

"you can use the cosine theorem to solve this problem."
c^2=a^2+b^2+2*a*b*cos theta
"where;"

a)

enter image source here

c=20
a=10
b=15
20^2=10^2+15^2+2*10*15*cos theta
400=100+225+300*cos theta
400=325+300*cos theta
400-325=300*cos theta
75=300*cos theta
cos theta=75/300=1/4
theta =75.52 " deg"

b)

a=10
b=15
c=12

enter image source here

12^2=10^2+15^2+2*10*15*cos theta
144=100+225+300*cos theta
144=325+300*cos theta
144-325=300*cos theta
-181=300*cos theta

cos theta=-181/300

theta=127.11