Question

If a projectile is shot at a velocity of `8 m/s` and an angle of `pi/3`, how far will the projectile travel before landing?

Answer 1

Range`= 3.2sqrt3`m

Explanation:

`v=8m/s` and `theta = pi/3`

Range`= (v^2sin2theta)/g`

`g~=10m/s^2`(not mentioned in question)

Range`= (64xxsin((2pi)/3))/10`

Range`= (64xxsqrt3)/(10xx2`

Range`= 3.2sqrt3`m