Question

What is the domain of `(-2x^2-2x+1)/(x^2+x)`?

Answer 1

For Domain,
`x^2+x!=0`

`x(x+1)!=0`

`x!=0` and `x!=-1`

So, `D_f=R-{0,-1}`

Answer 2

`x\ne -1 and x \ne 0`

Explanation:

You have to put `x^2+x \ne 0` because function is not definied in 0.
The way to solve is:
`x(x+1) \ne0`
And there are 2 solutions:

• `x\ne 0`
• `x+1 \ne 0` that becomes `x\ne-1`

`D: \mathbb{R} - {-1, 0}`