Question

Question #bcad8

Answer 1

`y=1/10x-13/5`

Explanation:

First find the gradient by doing change in y/change in x such as...

m(gradient)= `(-3-(-4))/(-4-(-14))`
=`1/10`

equation is y=`1/10x+b`

to find b you will need to substitute one of the points to the equation and solve for b
such as...

(-4,-3)
(x,y)

`=-3=1/10(-4)+b`
`=-3=-2/5+b`
`=-13/5=b`

equation is `y=1/10x-13/5`

you can also use `y-y1=m(x-x1)`(point-slope formula).

Answer 2

`y = \frac{1}{10}x-\frac{13}{5}`

Explanation:

Given two points `(x_1, y_1)` and `(x_2, y_2)` you have to use this formula here:
`\frac{y-y_1}{y_2-y_1}=\frac{x-x_1}{x_2-x_1}`

Let's substitute:
`\frac{y-(-4)}{-3-(-4)}=\frac{x-(-14)}{-4-(-14)}`

`\frac{y+4}{-3+4}=\frac{x+14}{-4+14}`

`\frac{y+4}{1}=\frac{x+14}{10}`

`y+4=\frac{x+14}{10}`

`10(y+4)=x+14`

`10y+40=x+14`

`10y=x+14-40`

`10y=x-26`

`y=\frac{1}{10}x-\frac{26}{10}`

The final result:
`y=\frac{1}{10}x-\frac{13}{5}`