Question #fbedc

1 Answer
Jan 3, 2018

#Au + 3/2Cl_2 -> AuCl_3#

Explanation:

Your balanced equation was given above

#Au + 3/2 Cl_2 -> AuCl_3# This is the balanced equation.

If you have 1.25 g of gold and 1.744 g of chlorine, it means you have 0.0063 mol of gold and 0.0246 mol of #Cl_2#.

For the balanced reaction you need 197 grams of gold (which is 1 mol) and 106.5 grams of #Cl_2# (which is #3/2# mol).

Therefore #Cl_2# is in excess. The needed amount of #Cl_2# is 0.671 gram to complete the reaction provided above. The excess amount is #=1.744-0.671 = 1.073# gram.

Note that gold has an atomic weight of 197 grams and #Cl_2# has a molecular weight of 71 grams.