If $a + b = 1$ $a+b=1$ and $a > 0$ $a>0$ and $b > 0$ $b>0$ can you prove this ? $[1+(1/(aⁿ))][1+(1/(bⁿ))] ≥ ( 1+2³)²$

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Answer 1 · 2018-01-05T21:57:02

No, I can't prove that because...

...it does not work. If I put $a=b=1/2$ and $n$ =1 I get $9$ on the left sideersus $81$ on the right.

Please check the question.

If a+b=1a+b=1a+b=1 and a>0a>0a>0 and b>0b>0 b>0 can you prove this ? [1+(1/(aⁿ))][1+(1/(bⁿ))] ≥ ( 1+2³)²[1+(1/(aⁿ))][1+(1/(bⁿ))] ≥ ( 1+2³)²