Question

Question #bbcd5

Answer 1

6.

Explanation:

If you were to have a function, `y=a*sin(bx)+c`,
We know that:
The amplitude of the function is `absa`.
The period of the function is `(2pi)/b`
The mid-line of the function is `c`.

Therefore, the `b` in this function is `pi/3`.
`(2pi)/(pi/3)=>2cancelpi*3/cancelpi=>6`
The period is 6.
graph{sin(pix/3) [-10, 10, -5, 5]}
In our graph here, we see that 6 is indeed the period.

It is important to know why this works!