How do you evaluate 12C8?

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Answer 1 · 2018-01-08T00:43:18

495

Given the formulas:
#"^nC_p=(n!)/(p!times(n-p)!)#

#n! =ntimes(n-1)times(n-2)times...times2times1#

The simplifications follows:

#"^12C_8=(12!)/(8!times(12-8)!)#

#"^12C_8=(12times11times10times9times8!)/(8!times4!)#

#"^12C_8=(12times11times10times9)/(4times3times2times1)#

#"^12C_8=(11.880)/(24)#

#"^12C_8=495#