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Answer 1 · 2018-01-08T17:58:40

#=# #(3sqrtx)/2-2x#

#f(x)=xsqrtx-x^2#

#D_f=[0,+oo)#

#f# is differentiable in #(0,+oo)# with:

#f'(x)=(x)'sqrtx+x(sqrtx)'-(x^2)'#

#=# #sqrtx+x/(2sqrtx)-2x#

#=# #(3sqrtx-4x)/2#

#=# #(3sqrtx)/2-2x#