Question

Question #7716e

Answer 1

`~~3M gal`

Explanation:

The problem can be solved using the formula:
`V=Pir^2h`

Given that the `"diameter (d) is " 92ft` and the `"height(h) is " 60ft`. Knowing that `d=2r`; so that, that `r=d/2`. Therefore, `r=(92ft)/2=46ft`

Referring to the formula, plug in its values to find the volume of the water that can be stored in the cylindrical tank; i.e.,
`V=Pir^2h`
`V=3.1416xx(46ft)^2xx60ft`
`V=3.1416xx2116ft^2xx60ft`
`V=398857.536ft^3`

Or change the ft^3 to gallon; where, `1ft^3=7.48gal` to visualize the volume of water in terms of this common unit.

`V=398857.536cancel(ft^3)xx(7.48052gal)/(1cancel(ft^3))`
`V=2,983,662 gal" of water"`