In the equation, Fe2O3 + 2Al → Al2O3 + 2 Fe, if 52.6 g of aluminum are used with excess iron oxide, how many grams of Fe2O3 will be converted to aluminum oxide?

1 Answer

#155.85# g

Explanation:

Let's consider the equation first.

#Fe_2O_3 + 2Al = Al_2O_3 + 2Fe#

It says that 2 moles of aluminium will react with 1 mole of Iron (III) Oxide to form 1 mole of Aluminium Oxide and 2 moles of Iron.

So, Unitary method.

#54# g Al will react with #rarr# #160# g of #Fe_2O_3#

#1# g Al will react with #rarr# #160/54# g of #Fe_2O_3#

#52.6# g Al will react with #rarr# #(160 * 52.6)/54# g of #Fe_2O_3# #approx# #155.85# g of #Fe_2O_3#

Hence Explained.