How do you solve #6(x+1)-2x-1=(x+15)+(x+16)#?

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Answer 1 · 2018-01-09T12:09:31

#x=13#

Expand the brackets:

#6(x+1)−2x−1=(x+15)+(x+16)#

#6x+6-2x-1=x+15+x+16#

Now clean up the equation:

#4x+5=2x+31#

Move the #2x# to the LHS and the #+5# to the RHS

#2x=26#

Therefore

#x=13#