The mean of 8 numbers is 41 The mean of 2 of the numbers is 29 What is the mean of the other 6 numbers?

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Answer 1 · 2018-01-09T19:30:47

Mean = 45

Let the 8 numbers be: # a, b, c,d,e,f,g,h #

# => (a+b+c+d+e+f+g+h) / 8 = 41 #

# => a+b+c+d+e+f+g+h = 328 #

Let the two of those numbers just be # g and h #

#=> (g+ h)/2 = 29 #

#=> g+h = 58 #

So # => a+b+c+d+e+f+color(blue)(g+h) = 328 # Becomes...

# => a+b+c+d+e+f+color(blue)(58) = 328 #

#=> a+b+c+d+e+f = 270 #

Mean of these six numbers...

#=> color(red)((a+b+c+d+e+f )/6 = 270/6 = 45 #

Answer 2 · 2018-01-09T23:19:16

45

The mean is that single value that if you multiply it by the count of values used to derive it you end up with their sum.

8 values with mean of 41
8 x 41 = 328 <-sum of all values.

2 values with mean of 29
2 x 29 = 58
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So the remaining 6 values must sum to 328 - 58 = 270

Thus the mean of the remaining 6 is #270 -: 6 = 45#