Question

Question #5321e

Answer 1

`a. 1cm^3`
`b. 20,000.04cm^2`
`c. 0.0001cm`

Explanation:

Per data given, the volume of the gold sheet can be solved directly through the formula:
`rho=m/V`; rearrange it to isolate the volume(V)
`V=m/rho`; plug in values
`V=(19.3cancel(g))/((19.3cancel(g))/(cm^3))`
`V=1cm^3`

Now, find the thickness `(T)` of the gold sheet. Given the measurements of `L=100cm` and `W=100cm`; `T` can be computed as follows:
`V=LxxWxxT`
`T=(V)/(LxxW)`
`T=(1cm^3)/(100cmxx100cm)`
`T=0.0001cm`

Finally, find the surface area (A) of the gold sheet
`A=2LW+2LT+2WT`
`A=(2)(100cm)(100cm)+(2)(100cm)(0.0001cm)+(2)(100cm)(0.0001cm)`
`A=20,000.04cm^2`