Question #5321e

1 Answer
Jarni Renz
Jan 10, 2018

#a. 1cm^3#
#b. 20,000.04cm^2#
#c. 0.0001cm#

Explanation:

Per data given, the volume of the gold sheet can be solved directly through the formula:
#rho=m/V#; rearrange it to isolate the volume(V)
#V=m/rho#; plug in values
#V=(19.3cancel(g))/((19.3cancel(g))/(cm^3))#
#V=1cm^3#

Now, find the thickness #(T)# of the gold sheet. Given the measurements of #L=100cm# and #W=100cm#; #T# can be computed as follows:
#V=LxxWxxT#
#T=(V)/(LxxW)#
#T=(1cm^3)/(100cmxx100cm)#
#T=0.0001cm#

Finally, find the surface area (A) of the gold sheet
#A=2LW+2LT+2WT#
#A=(2)(100cm)(100cm)+(2)(100cm)(0.0001cm)+(2)(100cm)(0.0001cm)#
#A=20,000.04cm^2#

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