How you solve this differential equation? $y'+5y=0$

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Answer 1 · 2018-01-10T14:58:55

$y=Ce^(−5x), C in RR$

$y'+5y=0$
$y'=-5y$
$(y')/y=-5$

$color(blue)((u')/u=ln'(u)$
$ln(y)'=-5$

$color(blue)"finding the primitive"$
$ln(y)=-5x+C$
$y=Ce^(-5x), C in RR$

How you solve this differential equation? y'+5y=0y'+5y=0