Question #33023

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Answer 1 · 2018-01-12T00:16:50

$1$ $1$

Given that $2 x - \frac{7}{4} x + \frac{7}{4} = 2$ $2x-7/4x+7/4 = 2$

Take the $\frac{7}{4}$ $7/4$ from the Left side to right side so that the $x$ $x$ terms and number terms can be separated.

Therefore, the equation becomes, $2 x - \frac{7}{4} x$ $2x-7/4x$ = $2 - \frac{7}{4}$ $2-7/4$

or, $\frac{8 x - 7 x}{4} =$ $(8x-7x)/4=$ $\frac{8 - 7}{4}$ $(8-7)/4$

or, $\frac{x}{4}$ $x/4$ = $\frac{1}{4}$ $1/4$

or $4 x =$ $4x=$ $4$ $4$ (cross-multiplying the denominator to opposite side)

or, $x$ $x$ = $\frac{4}{4}$ $4/4$ = $1$ $1$